Given is a Right triangle ΔACB with angle ∠ACB = 90 degrees.
Given that CD⊥AB, it means we have two Right triangles ΔCDA and ΔCDB.
Given angle ∠ACD = 30 degrees, it means ∠A = 60° and ∠B = 30°
Given side AC = 6 centimeters.
It says to find BD = ?
In Right triangle ΔCDA; CD is adjacent, AC is hypotenuse, ∠ACD = 30°
![Cos(\angle ACD)=(adjacent)/(hypotenuse) \\\\Cos(30^o)=(CD)/(AC) \\\\(√(3))/(2) =(CD)/(6) \\\\CD = 3√(3) \;cm](https://img.qammunity.org/2019/formulas/mathematics/high-school/kubnfnsy4ue7iakw2acbvdwbdruijngkgc.png)
In Right triangle ΔCDB; CD is opposite, BD is adjacent, ∠B = 30°
![Tan(\angle B) = (opposite)/(adjacent) \\\\Tan(30^o) = (CD)/(BD) \\\\(1)/(√(3)) = (3√(3))/(BD) \\\\Cross \;\;multiplying \\\\BD = √(3) * 3√(3) \\\\BD = 9 \;cm](https://img.qammunity.org/2019/formulas/mathematics/high-school/28dqtff1qo0crlb96sd8hecj12wafib0wg.png)
Hence, final answer is BD = 9 centimeters.