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Trig question ———————

Trig question ———————-example-1
User Pigfox
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1 Answer

7 votes

Answer:

1)
\cos(A) = 0.948(appx)

2)
\sin(A) = 0.316(appx)

3)
\tan(A) = 0.333(appx)

Explanation:

Using Pythagorean theorem ,

Hypotenuse =


\sqrt{ {6}^(2) + {2}^(2) } = √(36 + 4) = √(40) = 2 √(10)

We know that


  • \sin( \alpha ) = (side \: opposite \: to \: \alpha )/(hypotenuse \: of \: triangle)

  • \cos( \alpha ) = (side \: adjacent \: to \: \alpha )/(hypotenuse \: of \: triangle)

  • \tan( \alpha ) = (side \: opposite \: to \: \alpha )/(side \: adjacent \: to \: \alpha )

Where
\ alpha is an angle of tge triangle.

In the triangle given above ,
\ alpha = angle \: A . So,

1)
\cos(A) = (6)/(2 √(10) ) = (3)/( √(10) ) = 0.948(appx)

2)
\sin(A) = (2)/(2 √(10) ) = (1)/( √(10) ) = 0.316(appx)

3)
\tan(A) = (2)/(6) = (1)/(3) = 0.333(appx)

User Fahad Abid Janjua
by
8.4k points

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