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Witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2

A)log(3) 5+2 log(3)x
B)log(3) 5-2 log(3)x
C)2 log(3) 5-log(3)x
D)log(3) 5+log(3)x

User Omri L
by
5.6k points

2 Answers

2 votes
assuing you mean

log_(3)((5)/(x^2))
remember that
log((a)/(b))=log(a)-log(b)
also,
log(x^m)=(m)log(x)

so

log_(3)((5)/(x^2))=

log_(3)(5)-log_(3)(x^2)=

log_(3)(5)-2log{3}(x)

the answer is B
User Jake L
by
5.1k points
1 vote

Answer: The correct option is

(B)
\log_35-2\log_3x.

Step-by-step explanation: We are given to select the expression that is equivalent to the following logarithmic expression :


E=\log_3(5)/(x^2)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following properties of logarithms :


(i)~\log_a(b)/(c)=\log_ab-\log_ac,\\\\(ii)~\log_ab^c=c\log_ab.

From (i), we get


E\\\\=\log_3(5)/(x^2)\\\\\\=\log_35-\log_3x^2~~~~~~~~~~~~~~~~~~~~[\textup{Using property (i)}]\\\\\\=\log_35-2\log_3x.~~~~~~~~~~~~~~~~~~~~[\textup{Using property (ii)}]

Thus, the required equivalent expression is
\log_35-2\log_3x.

Option (B) is CORRECT.

User Sheikh Hasib
by
5.4k points