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A car turns a corner that has a radius of 5 m and experiences a centripetal acceleration of 20 m/s². If the radius of turn were increased to 10 m, calculate the centripetal acceleration.

User Mayuur
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2 Answers

5 votes

Answer:

10

Step-by-step explanation:

User Dmytro Pishchukhin
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4 votes
The centripetal acceleration is given by:

a_c = (v^2)/(r)
where
v is the velocity of the object
r is the radius of the trajectory

Initially, the car has an acceleration of
a_c = 20 m/s^2 and the radius of its trajectory is
r=5 m, so its velocity is

v= √(a_c r)= √((20 m/s^2)(5 m)) =10 m/s

Then the radius is increased to r=10 m, so the new centripetal acceleration is:

a_c = (v^2)/(r)= ((10 m/s)^2)/(10 m)= 10 m/s^2
User ChrisF
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