Question

A car turns a corner that has a radius of 5 m and experiences a centripetal acceleration of 20 m/s². If the radius of turn were increased to 10 m, calculate the centripetal acceleration.

Answer 1

10

Step-by-step explanation:

Answer 2

The centripetal acceleration is given by:

`a_c = (v^2)/(r)`
where
v is the velocity of the object
r is the radius of the trajectory

Initially, the car has an acceleration of
`a_c = 20 m/s^2` and the radius of its trajectory is
`r=5 m`, so its velocity is

`v= √(a_c r)= √((20 m/s^2)(5 m)) =10 m/s`

Then the radius is increased to r=10 m, so the new centripetal acceleration is:

`a_c = (v^2)/(r)= ((10 m/s)^2)/(10 m)= 10 m/s^2`