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2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15). a. How far did the robot travel in 2 seconds? b. What is the speed of the robot…

2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15). a. How far did the robot travel in 2 seconds? b. What is the speed of the robot…
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2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15).

a. How far did the robot travel in 2 seconds?

b. What is the speed of the robot?
Could you work it out

User Suresh Palemoni
by
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1 Answer

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 6 &,& 9~) % (c,d) &&(~ 10 &,& 15~) \end{array}~~~ % distance value d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ d=√((10-6)^2+(15-9)^2)\implies d=√(4^2+6^2)\implies d=√(52) \\\\\\ d\approx 7.2

what's its speed? well, it traveled √(52) in 2 seconds, so is simply √(52)/2, which is about 3.6 units per second.
User Colinf
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