Question

If 0.15 mol of I2 vapor can effuse through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to effuse under the same conditions?

Answer 1

It will take 19.03 seconds to effuse Cl2

Step-by-step explanation:

Step 1: Data given

0.15 mol of I2 effuses in 36 sec

Step 2: Calculate the time to effuse 0.15 mol of Cl2

R2/R1 = √(M1/M2)

R = 1/T

T1/T2 = √(M1/M2)

⇒ with T1 = the time needed to effuse I2 = 36 sec

⇒ with T2 = the time needed to effuse Cl2 = TO BE DETERMINED

⇒ with M1 = the molar mass of I2 = 253.8 g/mol

⇒ with M2 = the molar mass of Cl2 = 70.9 g/mol

36/X = √(253.8/70.9)

X= 19.03

It will take 19.03 seconds to effuse Cl2

Answer 2

It will take 19.044 sec for 0.15 mol of Cl2 to effuse under the same conditions

Step-by-step explanation:

From Graham's law of effusion, R1/R2 = √(M2/M1)

Since the number of moles is the same,

t2/t1 = √((M2/M1)

t1 (time taken for I2 to effuse) = 36 sec, M2 (molecular weight of Cl2)= 2×35.5 = 71, M1 (Molecular weight of I2) = 2×126.9 = 253.8

t2/36 = √(71/253.8)

t2/36 = 0.529

t2 = 36 × 0.529 = 19.044 sec