Answer:
![(21n)/(2) -(5n^(2) )/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gauygvsnk6bc6h46bojxuz0qtrmmw7xa5k.png)
Explanation:
- given ap series : 8,3,-2,-7,-12....up to n terms
[the second term should be +3 or else it wont form AP series]
first term in the series: 8
common difference : 3-8 = -5
total terms : n
- the formula for sum of n terms in an ap =
![(n)/(2) [2a+(n-1)d]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mp6gnobk0cgdblf8tb9xmpqyuvmkaqzg6v.png)
a: first term
d: common difference
n : total terms
- by substituting value in the above formula,
- sum of the A.P:
![(n)/(2) [2(8)+(n-1)-5]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fv12a8ng210txy63hn3r4ae8xh3gs2ofok.png)
![(n)/(2) [16+(n-1)(-5)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2hsxui0yjyyyso04dibj4v9mzuu5462wuw.png)
![(n)/(2) [16+(n-1)(-5)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2hsxui0yjyyyso04dibj4v9mzuu5462wuw.png)
![(n)/(2) [16+-5n+5]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rwtxv2gqvhxktjnvr8w84mz1v5mqwlfimk.png)
![(n)/(2) [21+-5n]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rpbif1lvhsv3suxlt5gpbu4f1per8s5nox.png)
=
![(21n)/(2) -(5n^(2) )/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gauygvsnk6bc6h46bojxuz0qtrmmw7xa5k.png)