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Two long thin wires carry currents of 2 A and 4 A out of the page. A magnetic force per meter of 5.0 × 10⁻⁴ ????/m acts on wire 2. What is the magnetic force per meter that acts on wire 1?

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Answer:

Step-by-step explanation:

Given

Current in two wires


I_1=2 A


I_2=4 A

Magnetic Force per unit length is given by


(F)/(l)=(\mu _0I_1I_2)/(2\pi r)

where
\mu _0=space\ permittivity

r=radial distance between wires


F_(12)=5* 10^(-4) N/m

Force on two wires will be equal in magnitudes but opposite in direction so Force on wire 1 duet o wire 2


F_(12)=5* 10^(-4) N/m

User Rok Kralj
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