Question

Determine the number of atoms of nickel (Ni) in a 5.05 grams solid nickel coin

show your work pls
1 mol = 6.02 x 1023 atoms
1 mol = molar mass on ptable
Does anyone know the answer to this?

Answer 1

To determine the number of atoms of nickel (Ni) in a 5.05-gram solid nickel coin, we calculate the molar mass of nickel (Ni), convert the mass of the coin to moles of Ni, and then use Avogadro's number to convert moles to atoms.

Step-by-step explanation:

To determine the number of atoms of nickel (Ni) in a 5.05 gram solid nickel coin, we need to use the mole concept. First, we calculate the molar mass of nickel (Ni) using the periodic table, which is 58.7 g/mol. Next, we convert the given mass of the coin to moles of Ni by dividing it by the molar mass: 5.05 g Ni / 58.7 g/mol = 0.086 moles Ni. Finally, we use Avogadro's number to convert moles to atoms: 0.086 moles Ni x 6.02 x 10^23 atoms/mol = 5.19 x 10^22 atoms of nickel (Ni) in the coin.

Answer 2

0.517× 10²³ atoms

Step-by-step explanation:

Given data:

Mass of nickel = 5.05 g

Number of atoms of nickel = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of nickel = 58.7 g/mol

by putting values,

Number of moles = 5.05 g/ 58.7 g/mol

Number of moles =0.086 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.086 mol × 6.022 × 10²³ atoms / 1mol

0.517× 10²³ atoms