Question

typical seawarer contains 2.7g of salt (sodium chloride,Nacl)per 100ml (100*10-3L).what is the molarity of Nacl in the ocean?​

Answer 1

The molarity of sodium chloride in the given sample of ocean seawater is approximately 0.462 M, calculated by first determining the moles of NaCl and then dividing by the volume of the solution in liters.

Step-by-step explanation:

To calculate the molarity of sodium chloride (NaCl) in ocean seawater, we can use the concentration given as 2.7 grams of NaCl per 100 milliliters of water. First, we convert the amount of NaCl to moles, knowing that the molar mass of NaCl is 58.44 grams per mole. We divide 2.7 grams by 58.44 grams/mole to find the number of moles:

Moles of NaCl = 2.7 g / 58.44 g/mol ≈ 0.0462 moles

Next, because the volume of the solution is 100 milliliters, we must convert that to liters by dividing by 1000:

Volume of solution in liters = 100 mL / 1000 = 0.1 L

Now we can calculate the molarity (M) of the NaCl solution:

Molarity (M) = moles of solute / liters of solution

Molarity (M) = 0.0462 moles / 0.1 L ≈ 0.462 M

The molarity of NaCl in this sample of ocean water is therefore about 0.462 M.

Answer 2

Molarity = 0.5 M

Step-by-step explanation:

Given data:

Mass of NaCl = 2.7 g

Volume = 100 mL(100×10⁻³L)

Molarity of solution = ?

Solution:

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 2.7 g/ 58.5 g/mol

Number of moles = 0.05 mol

Molarity = number of moles / volume in litte

Molarity = 0.05 mol / 100×10⁻³L

Molarity = 0.5 M