Question

The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Miranda (discovered by Kuiper in 1948) is in a circular orbit about Uranus at an altitude of 104,000 km above the planet's surface. Miranda has a mass of 6.6 X 10^19 kg and a radius of 236 km. a. Calculate the mass of Uranus from the given data. b. Calculate the magnitude of Miranda's acceleration due to its orbital motion about Uranus. c. Calculate the acceleration due to Miranda's gravity at the surface of Miranda. d. Do the answers to parts (b) and (c) mean that an object released 1 m above Miranda's surface on the side toward Uranus will fall up relative to Miranda? Explain.

Answer 1

`8.67791* 10^(25)\ kg`

`0.34589\ m/s^2`

`0.07903\ m/s^2`

Step-by-step explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

`r_m` = Radius of Miranda = 236 km

m = Mass of Miranda =
`6.6* 10^(19)\ kg`

Acceleration due to gravity is given by

`g=(GM)/(r^2)\\\Rightarrow M=(gr^2)/(G)\\\Rightarrow M=(9* 25360000^2)/(6.67* 10^(-11))\\\Rightarrow M=8.67791* 10^(25)\ kg`

The mass of Uranus is
`8.67791* 10^(25)\ kg`

Acceleration is given by

`a_m=(GM)/((r+h)^2)\\\Rightarrow a_m=(6.67* 10^(-11)* 8.67791* 10^(25))/((25360000+104000000)^2)\\\Rightarrow a_m=0.34589\ m/s^2`

Miranda's acceleration due to its orbital motion about Uranus is
`0.34589\ m/s^2`

On Miranda

`g_m=(Gm)/(r_m^2)\\\Rightarrow g_m=(6.67* 10^(-11)* 6.6* 10^(19))/(236000^2)\\\Rightarrow g_m=0.07903\ m/s^2`

Acceleration due to Miranda's gravity at the surface of Miranda is
`0.07903\ m/s^2`

No, both the objects will fall towards Uranus. Also, they are not stationary.