Question

a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same temperature T, and a temperature change of 0.100 is measured. What mass of water was in the vessel? ignore heat flow into the vessel, the thermometer etc.

Answer 1

1.34352 kg

Step-by-step explanation:

`m_w` = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

`\Delta T` = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

`m_v` = Mass of water in the vessel

Here the potential energy will balance the internal energy

`m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=(m_wgh-m_wc\Delta T)/(c\Delta T)\\\Rightarrow m_v=(m_wgh)/(c\Delta T)-m_w\\\Rightarrow m_v=(1* 9.81* 100)/(4186* 0.1)-1\\\Rightarrow m_v=1.34352\ kg`

Mass of the water in the vessel is 1.34352 kg