Question

A 16 Kb (=16,384 bit) memory array is designed as a square with an aspect ratio of one (number of rows is equal to the number of columns). The minimum number of address lines needed for the row decoder is________.

Answer 1

7

Step-by-step explanation:

The structure of memory chip is given by multiplying the number of rows and column ie M X N

he number of address line required for row decoder is n where M =
`2^(n)` or expressed in logarithmic form we have

`n= log_2 M`

In this case M=N since number of rows is equal to the number of columns

Therefore,
`M X N= M x M= M^(2)=16 kb=16384 b= 2^(4) * 2^(10)= 2^(14)`

`M^(2)= 2^(14)`

Therefore,

M=128

Since
`n=log_2 M`

`n=log_2 128=7`

Therefore, address lines should be at least 7