Question

A car travelling at 20.0 m/s starts to accelerate at 1.00 m/s2. After 5.00 s,

a) how fast is the car travelling and
b) the distance that it has travelled in that time. BTW,
c) how fast is 20.0 m/s in mph and
d) how far has the car travelled in ft

Answer 1

Step-by-step explanation:

Given

Initial speed of car
`u=20 m/s`

acceleration
`a=1 m/s^2`

`t=5 s`

acceleration is change in velocity over a period of time

`a=(v-u)/(t)`

`1=(v-20)/(5)`

`v=25 m/s`

(b)distance traveled s

`v^2-u^2=2 as`

`25^2-20^2=2* 1* s`

`s=(225)/(2)`

`s=112.5 m`

(c)20 m/s is 44.73 mph

as 1 m/s is 2.23 mph

(d)112.5 m in ft

369.1 ft

as 1 m is 3.28 ft