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To get an idea how big a farad is, suppose you want to make a 1-F air-filled parallel-plate capacitor for a circuit you are building. To make it a reasonable size, suppose you limit the plate area to What would the gap have to be between the plates? Is this practically achievable?

User DocWatson
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1 Answer

7 votes

Answer:

  • Gap between the plates
    8.85* 10^(- 16)\ m
  • No, practically not achievable

Solution:

As per the question:

Capacitance, C = 1 F

Area of the plate of the capacitor, A =
1\ cm^(2) = 1* 10^(- 4)\ m^(2)

Now,

To calculate the distance, D between the plates of a parallel plate capacitor:


C = (\epsilon_(o)A)/(D)

Thus


D = (\epsilon_(o)A)/(C)

where


\epsilon_(o) = permittivity of free space

Now,


D = (8.85* 10^(- 12)* 1* 10^(- 4))/(1)


D = 8.85* 10^(- 16)\ m

This distance much smaller and is practically not possible

User Hbin
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