Question

A race car starts from rest on a circular track of radius 478 m. The car’s speed increases at the constant rate of 0.747 m/s 2 . At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the speed of the race car

Answer 1

18.896ms-1

Step-by-step explanation:

The tangential acceleration of the car= 0.747ms-2

The centripetal acceleration is given by v^2/r

0.747= v^2/r

V= √0.747*478= 18.896ms-1