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A race car starts from rest on a circular track of radius 478 m. The car’s speed increases at the constant rate of 0.747 m/s 2 . At the point where the magnitudes of the centripetal and tangential accelerations
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A race car starts from rest on a circular track of radius 478 m. The car’s speed increases at the constant rate of 0.747 m/s 2 . At the point where the magnitudes of the centripetal and tangential accelerations are equal, find the speed of the race car

User Aolphn
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1 Answer

3 votes

Answer:

18.896ms-1

Step-by-step explanation:

The tangential acceleration of the car= 0.747ms-2

The centripetal acceleration is given by v^2/r

0.747= v^2/r

V= √0.747*478= 18.896ms-1

User Michael Sorens
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