Answer:
a)
![P(t) = 17900e^(0.04t)](https://img.qammunity.org/2020/formulas/mathematics/college/97sb7w378x9exkcnefpfg4n70xxiclzcqy.png)
b) The population estimated in 2008 is of 24651.
Explanation:
The population growth model may be given by the following exponential function:
![P(t) = P_(0)e^(rt)](https://img.qammunity.org/2020/formulas/mathematics/college/szvksyrn6a5y4r3bskxwoljqjfgbo9vfim.png)
In which P(t) is the population after t years,
is the initial population and r is the growth rate.
(A.) Find a function that models the population t years after 2000 (t=0 for 2000)
We have that:
. So
![P(t) = P_(0)e^(rt)](https://img.qammunity.org/2020/formulas/mathematics/college/szvksyrn6a5y4r3bskxwoljqjfgbo9vfim.png)
![P(t) = 17900e^(0.04t)](https://img.qammunity.org/2020/formulas/mathematics/college/97sb7w378x9exkcnefpfg4n70xxiclzcqy.png)
(B.) Use the function from part A to estimate the fox population in the year 2008.
2008 is 8 years after 2000. So:
![P(8) = 17900e^(0.04*8) = 24650.5](https://img.qammunity.org/2020/formulas/mathematics/college/6kzr0g33m5gv1c58vxghn8jq52oxzzdiwk.png)
The population estimated in 2008 is of 24651.