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A conducting single-turn circular loop with a total resistance of 4.50 Ω is placed in a time-varying magnetic field that produces a magnetic flux through the loop given by ΦB = a + bt2 − ct3, where a = 7.00 Wb, b = 12.5 Wb/s−2, and c = 5.50 Wb/s−3. ΦB is in webers, and t is in seconds. What is the maximum current induced in the loop during the time interval t = 0 to t = 1.70 s?

User Wmercer
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1 Answer

4 votes

Answer:

Step-by-step explanation:

Given

Resistance
R=4.5\Omega

Flux
\phi =a+bt^2-ct^3


\phi =7+12.5t^2-5.50t^3

emf induced
e=-(d\phi )/(dt)


e=-(d(7+12.5t^2-5.50t^3))/(dt)=25t-16.5t^2


i=(e)/(R)=-(1)/(R)* (d\phi )/(dt)


i=(1)/(4.5)* (25t-16.5t^2)

Maximum value of will be at
(di)/(dt)=0

therefore


(di)/(dt)=0


25-33t=0


t=0.757 s

i at
t=0.757 s


i=(1)/(4.5)* (25* 0.757-16.5(0.757)^2)


i=2.104 A

User DmitryK
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