Question

An astronaut goes out for a space-walk at a distance above the earth equal to the radius of the earth. What is her acceleration due to gravity at that point?

Answer 1

Answer:
`(g)/(4)`

Step-by-step explanation:

Let m be the mass of Astronaut

M=mass of earth

G=Gravitational constant

R=radius of Earth

Force Exerted by Earth on Astronaut

`F=(GmM)/(R^2)`

acceleration due to gravity is
`=(F)/(m)=g`

`g=(GM)/(R^2)`

When it is at
`r=2R`

`g'=(GM)/((2R)^2)`

`g'=(GM)/(4R^2)=(g)/(4)`