Question

Find the de Broglie wavelength λ for an electron moving at a speed of 1.00 x 10^6m/s. (Note that this speed is low enough that the classical momentum formula p=mv is still valid.) Recall that the mass of an electron is me=9.11 x 10^−31kg, and Planck's constant is h=6.626 x 10^−34J*s. Express your answer in meters to three significant figures.

Answer 1

De broglie wavelength will be 0.727 nm

Step-by-step explanation:

We have given speed of the electron
`v=10^6m/sec`

Mass of the electron
`m=9.11* 10^(-31)kg`

Plank's constant
`h=6.624* 10^(-34)Js`

We have to find the De Broglie wavelength

De Broglie wavelength is given by
`\lambda =(h)/(mv)=(6.624* 10^(-34))/(9.11* 10^(-31)* 10^6)=0.727* 10^(-9)m`

So wavelength will be 0.727 nm