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What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equilibrium position?

User Sjewo
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5.6k points

2 Answers

4 votes

Answer:

poopie

Step-by-step explanation:

User Campino
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6.4k points
5 votes

Answer:

Maximum force will be equal to 720 N

Step-by-step explanation:

We have given that spring constant
k=1.2* 10^4N/m

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by


F=kx=1.2* 10^4* 0.06=720N

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

User Lucas Walter
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5.2k points