Answer:
Maximum force will be equal to 720 N
Step-by-step explanation:
We have given that spring constant
![k=1.2* 10^4N/m](https://img.qammunity.org/2020/formulas/physics/high-school/swcw4gh26soh7sq9a820qa4tibpxq1ubxt.png)
Maximum stretch of the spring x = 6 cm = 0.06 m
We have to find the maximum force on the spring
We know that spring force is given by
![F=kx=1.2* 10^4* 0.06=720N](https://img.qammunity.org/2020/formulas/physics/high-school/oueglbk7dmjj7snaq1cfyo0ommisagddkq.png)
So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N