91.9k views
1 vote
Please help with the question in the picture!

Please help with the question in the picture!-example-1
User Ratojakuf
by
7.7k points

2 Answers

4 votes

Answer:

Cos S = 48/ 73

Explanation:

Given-

Δ QRS is right triangle.

∠ Q = 90°, QR ( Height ) = 55, QS ( Base ) = 48, RS ( Hypotenuse ) = 73

Cos S =
(Base)/(Hypotenuse) = (QS)/(RS)

Cos S =
(QS)/(RS)

∴ Cos S =
(48)/(73)

User Gmsantos
by
8.1k points
3 votes

Answer:

cosS = 48/73

Explanation:

cosS is asking for the cosine of angle S.

Cosine is one of the primary trig. ratios, which you can remember using the acronym:

SohCahToa

"o" is opposite.

"h" is hypotenuse.

"a" is adjacent.

Cosine is the "Cah" in the acronym.

cos = a/h

The adjacent side is touching the angle. The hypotenuse is the longest side.

cosS = adjacent/hypotenuse

= QS/RS

= 48/73 This number is already in its lowest terms.

User Ashish Gupta
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories