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Please help with the question in the picture!

Please help with the question in the picture!-example-1
User Ratojakuf
by
5.2k points

2 Answers

4 votes

Answer:

Cos S = 48/ 73

Explanation:

Given-

Δ QRS is right triangle.

∠ Q = 90°, QR ( Height ) = 55, QS ( Base ) = 48, RS ( Hypotenuse ) = 73

Cos S =
(Base)/(Hypotenuse) = (QS)/(RS)

Cos S =
(QS)/(RS)

∴ Cos S =
(48)/(73)

User Gmsantos
by
5.3k points
3 votes

Answer:

cosS = 48/73

Explanation:

cosS is asking for the cosine of angle S.

Cosine is one of the primary trig. ratios, which you can remember using the acronym:

SohCahToa

"o" is opposite.

"h" is hypotenuse.

"a" is adjacent.

Cosine is the "Cah" in the acronym.

cos = a/h

The adjacent side is touching the angle. The hypotenuse is the longest side.

cosS = adjacent/hypotenuse

= QS/RS

= 48/73 This number is already in its lowest terms.

User Ashish Gupta
by
4.8k points