Graph the line passing through (-1,-5) whose slope is m= 1/5

Question

asked May 9, 2020 196k views

2 Answers

Camara · Answer 1 · 2020-05-12T23:35:11+0000

Answer:

The graph is in the attachment.

Explanation:

We only need two points to draw a graph of the line.

The slope-point form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have m = 1/5 and the point (-1, -5) → x₁ = -1, y₁ = -5

Substitute:

$y-(-5)=(1)/(5)(x-(-1))\\\\y+5=(1)/(5)(x+1)$

We given first point (-1, -5).

Calculate other point.

Put x = 4 to the equation of a line:

y+5=(1)/(5)(4+1)

y+5=(1)/(5)(5)

y+5=1 subtract 5 from both sides

y=-4

Therefore we have second point (4, -4).