If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of Fe(OH)2 would be formed? A. 291.44 g Fe(OH)2 B. 507 g Fe(OH)2 C. 499.06 g Fe(OH)2 D. 359.48 g Fe(OH)2

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asked Sep 26, 2020 100k views

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If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of Fe(OH)2 would be formed?

A. 291.44 g Fe(OH)2
B. 507 g Fe(OH)2
C. 499.06 g Fe(OH)2
D. 359.48 g Fe(OH)2

Chemistry
middle-school

Bretterer asked

by Bretterer

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2 Answers

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359.48 g Fe(OH)2. I just took this test

Rgantla answered Sep 29, 2020

by Rgantla

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6 votes

Answer: 359.29g

Explanation: the options are not correct. See attachment for explanation.

If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how-example-1

Srikanta answered Oct 1, 2020

by Srikanta

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