If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of Fe(OH)2 would be formed? A. 291.44 g Fe(OH)2 B. 507 g Fe(OH)2 C. 499.06 g Fe(OH)2 D. 359.48 g Fe(OH)2

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Sep 26, 2020 100k views

0 votes

If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of Fe(OH)2 would be formed?

A. 291.44 g Fe(OH)2
B. 507 g Fe(OH)2
C. 499.06 g Fe(OH)2
D. 359.48 g Fe(OH)2

Chemistry
middle-school

Bretterer asked

by Bretterer

5.0k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

5 votes

359.48 g Fe(OH)2. I just took this test

Rgantla answered Sep 29, 2020

by Rgantla

5.4k points

0 Comments

Please log in or register to add a comment.

6 votes

Answer: 359.29g

Explanation: the options are not correct. See attachment for explanation.

If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how-example-1

Srikanta answered Oct 1, 2020

by Srikanta

5.1k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.7m questions

7.5m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions