Answer:
a) initial mass = 34.85 gm, final mass = 3.48gm
b)
Step-by-step explanation:
At the initial state, the:
Pressure, p1 = 1000kPa,
Temperature, T1 = 1000K,
Volume, V1 = 10 m³
The mass of air in the tank can be evaluated using;
m1 = (p1 x V1) /(R x T1)
m1 = (1000 x 10)/(287 x 1000)
Therefore, m1 = 34.85g
At the final state,
Pressure, p2 = 100kPa,
Temperature, T2 = 1000K,
Volume, V2 = 10 m³
The mass of air in the tank is given by;
m2 = (p2 x V2) / R x T2
m2 = (100 x 10)/ 287 x 1000
Therefore m2 = 3.48 gm