Question

13. Bari kicked a ball and its leaves the ground at an angle 30° with a velocity of 20 m/s.

Find hang time of the ball
11 Pari Iricked a ball and its leaves the ground at an angle 30° with a velocity of 20. m/s.


I have a physics test upcoming and I’m particularly stuck on this question and I would be grateful if anyone could help me out.

Answer 1

The hang time is 2.04 seconds

Step-by-step explanation:

2-D Motion

It referred to as a situation where an object is launched in such a way it describes a curve, reaches a top height and then returns to ground level after traveling a certain distance x away from the launch point.

Let
`v_o` be the launching speed forming an angle
`\theta` with the horizontal reference. The hang time (time the object remains in the air) is given by

`\displaystyle t_h=(2V_(oy))/(g)`

Since

`\displaystyle v_(oy)=v_o\ sin\theta`

Then

`\displaystyle t_h=(2v_o\ sin\theta )/(g)`

We'll use the given values

`\displaystyle v_o=20\ m/s\ ,\ \theta =30^o`

`\displaystyle t_h=(2(20)sin30^o)/(9,8)`

`\displaystyle t_h=2.04\ sec`

The hang time is 2.04 seconds