Total volume in two glasses is 740 ml
Solution:
Given that ratio of the volume of soda in glass A to the volume of glass B is 8/3 to 7/2
There is 320mL of soda in glass A
To find: total volume in the two glasses
From given information,
volume of soda in glass A : volume of soda in glass B =
![(8)/(3) : (7)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5r6ltiuv18yhfoioj93i6ajeqydtoup2mb.png)
Ratio a : b can be written in fraction as
![(a)/(b)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3ieqiim7n24kz6w1yrgbi037zxpcc432h0.png)
Similarly,
![\frac{\text {volume of soda in glass } A}{\text {volume of soda in glass } B}=(8 / 3)/(7 / 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j8ke5an152ld8kmzlib0h4ufsjla4mvvtm.png)
![\frac{\text {volume of soda in glass } A}{\text {volume of soda in glass } B}=((8)/(3))/((7)/(2))=(8)/(3) * (2)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bhkzup1tcb1smt8z8p2xr8cqs3ke0zbyqd.png)
![\frac{\text {volume of soda in glass } A}{\text {volume of soda in glass } B}=(16)/(21)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/er4br8s6kzouuyu8l1y601jyzci6rs4c2q.png)
Given that There is 320mL of soda in glass A
So substituting in above equation,
![\frac{320}{\text { volume of soda in glass } B}=(16)/(21)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vr27c3ayiecxv4vbmi8esd889gaqvzi65p.png)
![\text {volume of soda in } g \text {lass } B=320 * (21)/(16)=420](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bzgcgy4lv2t8udytig60h1wvps3uyipf6a.png)
Thus volume of soda in glass B = 420 ml
Total volume in two glasses:
total volume in the two glasses = volume of soda in glass A + volume of soda in glass B
total volume in the two glasses = 320 ml + 420 ml = 740 ml
Thus total volume in two glasses is 740 ml