Question

What is the 100th term of the sequence with a1 = 222 and d = -5?

-273

-278

717

722

Answer 1

`u_(n) = a + (n - 1)d\\\\n = 100, a = 222, d = -5\\\\</p><p>Substitute the values in.\\\\</p><p>u_(100) = 222 + (100 - 1)(-5)\\\\</p><p>u_(100) = 222 + (99)(-5)\\\\</p><p>u_(100) = 222 + (99)(-5)\\\\</p><p>u_(100) = 222 +-495\\\\</p><p>u_(100) = -273`

Answer 2

-273

222

217

212

207

202

197

192

187

182

177

172

167

162

157

152

147

142

137

132

127

122

117

112

107

102

97

92

87

82

77

72

67

62

57

52

47

42

37

32

27

22

17

12

7

2

-3

-8

-13

-18

-23

-28

-33

-38

-43

-48

-53

-58

-63

-68

-73

-78

-83

-88

-93

-98

-103

-108

-113

-118

-123

-128

-133

-138

-143

-148

-153

-158

-163

-168

-173

-178

-183

-188

-193

-198

-203

-208

-213

-218

-223

-228

-233

-238

-243

-248

-253

-258

-263

-268

-273

Explanation: