Question

The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 feet, what is the length, AB of the rectangular lot?

Answer 1

`AB=131\ ft`

Explanation:

we know that

The perimeter of the rectangular lot is

`P=2(AB+BC)` ----> equation A

where

AB is the length

BC is the width

we have

`AB=2BC-1` ---> equation B

`P=394\ ft` ----> equation C

substitute equation B and equation C in equation A

`394=2(2BC-1+BC)`

solve for BC

`394=2(3BC-1)`

`394=6BC-2`

`6BC=396`

`BC=66\ ft`

Find the value of AB

`AB=2BC-1`

`AB=2(66)-1`

`AB=131\ ft`