Answer:
The Dimension of the pool is approximately 5.37 feet and 8.37 feet.
Explanation:
Given:
Area of Swimming Pool = 116 sq. ft
The length of a swimming pool is 3 feet longer than it's width.
Let the width of swimming pool be 'x' feet.
∴Length =
feet
Also given :
The swimming pool is surrounded by a deck that is 2 feet wide.
Hence we can say the deck is surrounded 2 feet on all 4 sides.
hence;
Length of swimming pool will become =

Width of swimming pool will become =

Since Swimming pool is in rectangular shape.
Now we know that area of Swimming pool is equal to length multiplied by width.
Framing in equation form we get;

Substituting the given values we get;

Solving the equation we get;

Now solving this equation by using quadratic formula we get;
According to the Quadratic Formula, x , the solution for
, where a, b and c are numbers, often called coefficients, is given by :

in our case a = 1 , b = 11 and c = -88


, rounded to 4 decimal digits, is 21.7486.

Two real solutions:

OR

Since width of the swimming pool cannot be negative value
hence we will consider

Rounding to nearest hundred we get;
Width of Swimming pool = 5.37 feet
Length of Swimming pool = 3+5.37 =8.37 feet
Hence The Dimension of the pool is approximately 5.37 feet and 8.37 feet.