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From a vantage point very close to the track at a stock car race, you hear the sound emitted by a moving car. You detect a frequency that is 0.844 times smaller than that emitted by the car when it is stationary. The speed of sound is 343 m/s. What is the speed of the car?

User SecureFish
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1 Answer

7 votes

Answer:

Step-by-step explanation:

Given

Apparent Frequency
f'=0.844 f_0

speed of sound
v=343 m/s

Applying Doppler Effect Formula


f'=f_0((v+v_0)/(v-v_s))

where
v_0=speed of observer


v_s=speed of source

here
v_o=0 as he is listening and at rest


0.844f_0=f_0((343+0)/(343-v_s))


343-v_s=406.39


v_s=-63.39 m/s

i.e. car is moving away from observer with 63.99 m/s

User Selene
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