Question

There are 4 red and 6 green marbles in a jar. What is the probability of drawing two green marbles, with replacement?

2/5

9/25

3/5

4/25
Select EACH correct answer

Answer 1

`(9)/(25)`

Explanation:

Number of red balls = 4

Number of green balls = 6

Total number of balls = 6+4 =10

Probability of drawing a green marble is given as

⇒
`(Number\ of\ green\ balls)/(Total\ number\ of\ balls)`

⇒
`(6)/(10)`

The ball is replaced after drawing.

Probability of drawing a green ball a second time will be:

⇒
`(Number\ of\ green\ balls)/(Total\ number\ of\ balls)`

⇒
`(6)/(10)`

Thus, probability of drawing 2 green balls with replacement can be given as:

⇒ (Probability of drawing a green marble)
`*` (Probability of drawing a green ball a second time)

⇒
`(6)/(10)*(6)/(10)`

⇒
`(36)/(100)`

Simplifying fraction by dividing numerator and denominator by their GCF.

⇒
`(36/ 4)/(100/ 4)`

⇒
`(9)/(25)` (Answer)