Answer:
Length of poster is 9 inches and width of the poster is 3 inches.
Length of banner is 10 inches and width of the banner is 2 inches.
Explanation:
Given:
Perimeter of Banner =24 in.
Perimeter of poster = 24 in.
we need to find the dimensions of poster and banner.
First we will find the dimension of poster.
Now Given:
A rectangular poster is 3 times as long as it is wide.
Let the Width of poster be
.
Length of the poster =
![3p](https://img.qammunity.org/2020/formulas/mathematics/high-school/4yc9jg599qhkhawc1fcyd9ttktkckcry1e.png)
Perimeter of poster = 24 in.
But perimeter of poster is equal to twice the sum of length and width.
framing in equation form we get;
![2(p+3p)=24\\\\2(4p)=24\\\\8p=24\\\\p=(24)/(8) = 3\ in.](https://img.qammunity.org/2020/formulas/mathematics/high-school/fxf5o67rjw49yphpc6gcodvgwccz6l7nby.png)
Now width of poster = 3 inches
Length of the poster =
![3p = 3*3 =9\ inches](https://img.qammunity.org/2020/formulas/mathematics/high-school/nnmpuetq2yjpidkkzfmq91ujk5ff94zht9.png)
Hence Length of poster is 9 inches and width of the poster is 3 inches.
Now we will find the dimension of Banner.
Now Given:
A rectangular banner is 5 times as long as it is wide.
Let the Width of Banner be
.
Length of the banner =
![5b](https://img.qammunity.org/2020/formulas/mathematics/high-school/111lop0pwazlwow030yorzdw8d5eltsvbl.png)
Perimeter of banner = 24 in.
But perimeter of banner is equal to twice the sum of length and width.
framing in equation form we get;
![2(b+5b)=24\\\\2(6b)=24\\\\12b=24\\\\b=(24)/(12) = 2\ in.](https://img.qammunity.org/2020/formulas/mathematics/high-school/j0i8gp04naio20h98vrmdxpz3ztlsbzd4p.png)
Now width of banner = 2 inches
Length of the banner =
![5b = 5*2 = 10\ inches](https://img.qammunity.org/2020/formulas/mathematics/high-school/3c969n666jhjjb3gckigvwsd6zuqhojxzq.png)
Hence Length of banner is 10 inches and width of the banner is 2 inches.