Answer:
![2√(2)\ ft\ longer](https://img.qammunity.org/2020/formulas/mathematics/high-school/x570010e4obsih9zi5gavikzvuimr7s8o2.png)
Explanation:
Area Of A Cube
Suppose a cube with side length s, the area of one side is
![A_s=s^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/ey31gsesif5edxbyoxrps8dys14kzqquae.png)
Since the cube has 6 sides, the total area is
![A=6A_s=6s^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/vqw4x1c0zc8lm9x7xtbb4nb6mwzjq758vo.png)
But if we have the area, we can solve the above formula for s to get
![A=6s^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/xjw26obmwt039dmi2d988gujk9v7esb02p.png)
![\displaystyle s=\sqrt{(A)/(6)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/3204jzcy6wc7tttkfqobs5p6h4fpkox3n9.png)
We have two different cubes with areas 1,200 square inches and 768 square inches. Let's compute their side lengths
![\displaystyle s_1=\sqrt{(1,200)/(6)}=√(200)](https://img.qammunity.org/2020/formulas/mathematics/high-school/nsyc05mpwz7aofipc3ts49cy514ieumy3k.png)
![\displaystyle s_1=10√(2)\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/fmuoa3o5e1ld7vhhtlxphemuer71sruqii.png)
![\displaystyle s_2=\sqrt{(768)/(6)}=√(128)](https://img.qammunity.org/2020/formulas/mathematics/high-school/q068ozcdkhwz4wdjt4bqbd4qybs0468p2p.png)
![\displaystyle s_2=8√(2) ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/2wmcdqwru2elt3bnju3az4tus48okbd60g.png)
The difference between them is
![10√(2)\ ft-8√(2)\ ft=2√(2)\ ft\approx 2.83\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/vbbs7hk5v29ute4ahjrbw3vn9xfpnevyqk.png)
The side of the cube with area 1,200 square inches is
longer then the side of the cube with area 768 square inches