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How many atoms are there in 18 grams of silver

1 Answer

3 votes

Answer:

Number of atoms=
<strong>1.004* 10^(23)</strong> atoms

Step-by-step explanation:

1 mole is the mass of substance which contain
<strong>6.022* 10^(23)</strong>

particles of that substance.Its symbol is 'n'.

Here the quantity
<strong>6.022* 10^(23)</strong> is called Avogadro number and it is denoted by
<strong>N_(0)</strong>.

Mass of the substance in grams is called is molar mass.It is denoted by'M'

Moles can be calculated by :

1)
<strong>n=(given\ mass)/(molar\ mass)=(w)/(M)</strong>

2)
<strong>n=(Number\ of\ particles)/(Avogadro\ number)=(N)/(N_(0))</strong></p><p>

compare 1) and 2) formula, we get


<strong>\frac{N}{N_(0)=(w)/(M)</strong>[tex].................(i)</p><p>For<strong> silver (Ag), M=107.86 g</strong></p><p><strong>w=18 g &nbsp;</strong>(given) and [tex]<strong>{N_(0)=6.022* 10^(23)</strong>

Put the values of w,M and
{N_(0)[tex] in equation (i) and solve for N</p><p>[tex]\<strong>frac{N}{6.022* 10^(23)}=(18)/(107.86)</strong>


<strong>N=(18)/(107.86)* 6.022* 10^(23)</strong>


<strong>N= 1.004* 10^(23)</strong>[tex]</p><p><strong>Hence Number of atoms of silver</strong>= [tex]<strong>1.004* 10^(23)</strong> atoms

User Abhijit Mazumder
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