Question

4X²+ 3x² - 6x + 8

Part A: State if (x+3) is a factor of the polynomial
Part B: What is the if the remainder polynomial
if divided by (x+3)

Answer 1

Below.

Explanation:

4X²+ 3x² - 6x + 8

Part A.

If x+3 is a factor then f(-3) = 0.

f(-3) = 4(-3)^3 + 3(-3)^2 - 6(-3) + 8

= -108 + 27 + 18 + 8

= -55

So x+3 is NOT a factor.

Part B.

We worked this out in Part A:

-55.