Question

Six times a larger number is equal to the sum of a smaller number and 18. The difference of twice the larger number and the

smaller number is 6. Let x represent the smaller number and y represent the larger number. Which equations represent the
situation?
y = 6x+18
y = 2x-6
o y = 6(x+18)
y = 2(x-6)
oy-ax+3
y-1x+6

Answer 1

the correct answer is D

Explanation:

Answer 2

The set of equations that represent this situation is:

`y = (1)/(6)x + 3`

`y = (1)/(2)x + 3`

Solution:

Let "x" represent the smaller number

Let "y" represent the larger number

Given that,

Six times a larger number is equal to the sum of a smaller number and 18

Here "times" represents multiplication

Six times a larger number = sum of a smaller number and 18

6 x larger number = smaller number + 18

6y = x + 18

Thus,

`y = (1)/(6)(x + 18)\\\\y = (1)/(6)x + 3`

Also given that difference of twice the larger number and the smaller number is 6

twice the larger number - smaller number = 6

2y - x = 6

Thus,

2y = x + 6

`y = (1)/(2)(x + 6)\\\\y = (1)/(2)x + 3`

Thus the set of equations that represent this situation is:

`y = (1)/(6)x + 3`

`y = (1)/(2)x + 3`