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A 40.-g sample of impure KClO3 (solubility = 7.1 g per 100 g H2O at 20° C) is contaminated with 19 percent of KCl (solubility = 25.5 g per 100 g of H2O at 20° C). Calculate the minimum quantity of 20° C water needed to dissolve all the KCl from the sample. (Assume that the solubilities are unaffected by the presence of the other compound.)

User Allejo
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1 Answer

2 votes

Answer:

29.80 grams is the minimum quantity of 20° C water needed to dissolve all the KCl from the sample.

Step-by-step explanation:

Mass of impure sample of
KClO_3 = 40 g

Percentage of KCl impurity sample = 19%

Mass of KCl impurity sample = 19% of 40 g =
(19)/(100)* 40 g=7.6 g

Solubility of KCl in 100 grams of water at 20° C = 25.5 g.

Mass of water required dissolve of 1 gram KCl =
(100 g)/(25.5)

The mass of water required dissolve 7.6 g of KCl at 20°C=


(100 g)/(25.5)* 7.6 =29.80 g

29.80 grams is the minimum quantity of 20° C water needed to dissolve all the KCl from the sample.

User Danielorn
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