Cost of 1 adult ticket is $ 7 and cost of 1 student ticket is $ 3
Solution:
Let "a" be the cost of 1 adult ticket
Let "s" be the cost of 1 student ticket
Given that,
4 adult and 10 student tickets cost 58$ overall on the first day
So we can frame a equation as:
4 adult ticket x cost of 1 adult ticket + 10 student ticket x cost of 1 student ticket = $ 58
4a + 10s = 58 ------ eqn 1
On the second 5 adult and 1 student cost 38$ overall
So we can frame a equation as:
5 adult ticket x cost of 1 adult ticket + 1 student ticket x cost of 1 student ticket = $ 38
5a + 1s = 38 ------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "a" and "s"
Multiply eqn 2 by 10
50a + 10s = 380 ---- eqn 3
Subtract eqn 1 from eqn 3
50a + 10s = 380
4a + 10s = 58
( - ) --------------------
46a = 322
a = 7
Substitute a = 7 in eqn 1
4a + 10s = 58
4(7) + 10s = 58
28 + 10s = 58
10s = 58 - 28
10s = 30
s = 3
Thus cost of 1 adult ticket is $ 7 and cost of 1 student ticket is $ 3