89.2k views
2 votes
If ((3+2i/2-3i) + (5-i/2+3i)) * a/b, then a=? and b=?

If ((3+2i/2-3i) + (5-i/2+3i)) * a/b, then a=? and b=?-example-1

1 Answer

2 votes

Answer:


a=13\\ \\b=7-4i

Explanation:

Consider the expression in the brackets:


(3+2i)/(2-3i)+(5-i)/(2+3i)

Simplify it:


(3+2i)/(2-3i)+(5-i)/(2+3i)\\ \\=((3+2i)(2+3i)+(5-i)(2-3i))/((2-3i)(2+3i))\\ \\=(6+9i+4i+6i^2+10-15i-2i+3i^2)/(2^2-(3i)^2)\\ \\=(16-4i+9i^2)/(4-9i^2)\\ \\=(16-4i-9)/(4-9(-1))\\ \\=(7-4i)/(13)

So,


a=13\\ \\b=7-4i

User Tam Bui
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories