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Given: LN⊥KM,KL≅ML Prove: ΔKLN≅ΔMLN

Given: LN⊥KM,KL≅ML Prove: ΔKLN≅ΔMLN-example-1

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Answer:

The Proof is given below.

Explanation:

Given:

LN⊥KM,

KL≅ML

To Prove:

ΔKLN≅ΔMLN

Proof:

In Δ KLN and Δ MLN

KL ≅ ML ....……….{Given i.e Hypotenuse }

LN ≅ LN …………..{Reflexive Property}

∠ LNK ≅ ∠ LNM ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}

Δ KLN ≅ Δ MLN ….{By Hypotenuse Leg Theorem} ....Proved

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