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Find the value of x in the isosceles triangle shown below​

Find the value of x in the isosceles triangle shown below​-example-1
User Tirrel
by
5.3k points

2 Answers

3 votes

Answer:

10

Explanation:

Trust me

User Thattolleyguy
by
6.3k points
6 votes

Answer:

22.18 = x

Explanation:

a^2 + (b)^2 = (x/2)^2

a = sqrt(74)

b = 7

x/2 = ?

(74)[^1/2]^2 = 74

b^2 = 7^2 = 49

74 + 49 = (x/2)^2 Substitute into a^2 + b^2 = c^2

123 = (x/2)^2 Combine like terms

(123^0.5) = x/2 Take the square root of both sides.

11.09 = x/2 Multiply both sides by 2

11.09*2 = x

22.18 = x The full length of the base of the triangle is 22.18

User MrCheese
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5.9k points