Question

Δ→ Δ→
5N 6N
what is the net force?

Answer 1

The net force acting on the body, F = 11 N

Step-by-step explanation:

Given data,

The force acting on the body, f = 5 N

Another force acting on the body, f' = 6 N

The direction of both forces is in the same direction.

The net force is given by the resultant vector,

`F= \sqrt{f^(2) + f'^(2) + 2 ff' Cos \theta}`

`F= \sqrt{f^(2) + f'^(2) + 2 ff'` (∵ θ = 0)

`F=\sqrt{(f + f')^(2) }`

F = f + f'

= 5 N + 6 N

= 11 N

Hence, the net force acting on the body, F = 11 N