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What are the intercepts of the equation 7x-2y-14z=56?

User Flavien
by
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1 Answer

4 votes

Answer:

The intercepts are

(8,0,0),(0,-28,0),(0,0,-4)

Explanation:

we have


7x-2y-14z=56

step 1

Find the x-intercept

The x-intercept is the value of x when the value of y and z are equal to zero

so

For y=0, z=0

substitute


7x-2(0)-14(0)=56

solve for x


7x=56


x=8

The x-intercept is (8,0,0)

step 2

Find the y-intercept

The y-intercept is the value of y when the value of x and z are equal to zero

so

For x=0, z=0

substitute


7(0)-2y-14(0)=56

solve for y


-2y=56


y=-28

The y-intercept is (0,-28,0)

step 3

Find the z-intercept

The z-intercept is the value of z when the value of x and y are equal to zero

so

For x=0, y=0

substitute


7(0)-2(0)-14z=56

solve for z


-14z=56


z=-4

The y-intercept is (0,0,-4)

therefore

The intercepts are

(8,0,0),(0,-28,0),(0,0,-4)

User John Jiang
by
7.6k points