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How do I graph the linear equation y=-1/2x + 4

User ClayRay
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1 Answer

4 votes

Answer:

The Two points for the line
y =(-1)/(2)x+4 are

point A( x₁ , y₁) ≡ ( 0 , 4)

point B( x₂ , y₂) ≡ (8 , 0)

The Graph is attached below.

Explanation:

Given:


y =(-1)/(2)x+4........... equation of a line Given

Let the points be point A, and point B

To Find:

point A( x₁ , y₁) ≡ ?

point B( x₂ , y₂) ≡ ?

Solution:

For Drawing a graph we require minimum two points but we will have here.

For point A( x₁ , y₁)

Put x = 0 in the given equation we get


y =(-1)/(2)0+4\\\\y=4

∴ point A( x₁ , y₁) ≡ ( 0 , 4)

For point B( x₂ , y₂)

Put y= 0 in the given equation we get


0 =(-1)/(2)x+4\\\\x=8

∴ point B( x₂ , y₂) ≡ (8 , 0)

Therefore,

The points for the line
y =(-1)/(2)x+4 are

point A( x₁ , y₁) ≡ ( 0 , 4) (blue color point on the graph)

point B( x₂ , y₂) ≡ (8 , 0) (green color point on the graph)

The Graph is attached below..

How do I graph the linear equation y=-1/2x + 4-example-1
User Alecov
by
8.2k points

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